Question 133611
I'll assume you are Given: {{{(2+3i)/i}}}
{{{((2+3i)/i) * 1 }}}
{{{((2+3i)/i) * (i/i) }}}
{{{((2i+3i^2)/i^2)}}}
{{{(2i - 3)/(-1) }}}
{{{ 3 - 2i }}}

If the problem was, in fact {{{2+3i/i}}}
then the answer is simply {{{ 2 + 3}}} = {{{5}}}