Question 133277
Please solve with steps
2(4^v+1) = 1
:
I assume you mean:
{{{2(4^(v+1))}}} = 1
Divide both sides by 2 and you have;
{{{4^(v+1) = 1/2}}}
Using logs:
{{{log(4^(v+1)) = log(1/2)}}}
log equivalent of exponents:
{{{(v+1)*log(4) = log(1/2)}}}
Find the logs
.602(v+1) = -.301
:
Divide both sides by .602
{{{v + 1 = -.301/.602}}}
v + 1 = -.5
:
v = -.5 - 1
:
v = -1.5
:
Check solution on a calc: Enter 2(4^(-1.5+1)) = 1