Question 133451
We'll do slope intercept on the first one.
{{{4x+y =5}}}
{{{ y = -4x +5 }}}  and in the form {{{y = mx +b}}}
so, intercept = 5 ; slope = -4
{{{graph(300,200, -10, 10, -10 ,10, -4x+5)}}}

We'll do the second one using substitution:
{{{3x-2y=6}}}
set x = 0 so {{{-2 = 6}}}  and {{{y=-3}}} so the first point is (0,-3)
set y = 0. so {{{3x = 6}}} and {{{x=2}}}. so the second point is (2,0)
Plot those two points and draw the line that includes them
{{{graph(300,200, -10, 10, -10 ,10, 3x/2 -3)}}}

The third one is a bit different. There is no specific value for x. Every point includes y=5/3. This is a horizontal line where with a y of 5/3.
{{{graph(300,200, -10, 10, -10 ,10, 5/3)}}}

Use slope intercept on 4. Look at problem 1 if you need more help with it