Question 133440
the bases are the same (6) so the arguments are equal


7=6^(x+1)+6^(x+2)


6^(x+2)=(6(x+1))(6^1)=6(6^(x+1))


substituting __ 7=6^(x+1)+6(6^(x+1)) __ 7=7(6^(x+1))


dividing by 7 __ 1=6^(x+1) __ taking log __ log(1)=(x+1)log(6)


dividing by log(6) __ (log(1))/(log(6))=x+1 __ 0=x+1