<PRE><B>Question 133440</B>
log6 7 = log6(6^x+1 plus 6^x+2)
It looks like (6^(x+1) + 6^(x+2)) is the inverse log on the right side.
If that is true you get:
(6^(x+1) + 6^(x+2)) = 7
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Now take the log(base 6) of both sides to get:
log6 [6^(2x+3)] = log7/log6
2x+3 = 1.08603
2x = -1.9139
x = -0.95698...
Cheers,
Stan H.
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