Question 133438
the logs are equal so the quantities are equal


-2500=5^(n+2)-5^(n+3)


5^(n+3)=5^(n+2)(5^1)=5(5^(n+2))


substituting __ -2500=5^(n+2)-5(5^(n+2)) __ -2500=-4(5^(n+2))


dividing by -4 __ 625=5^(n+2)


taking log __ log(625)=(n+2)(log(5)) __ dividing by log(5) __ (log(625))/(log(5))=n+2


4=n+2 __ subtracting 2 __