Question 133340
Given: log2 1056 = log2(2^a+5 plus 2^a)

So:
{{{1056 = 2^(a+5) + 2^a }}}
{{{1056 = (2^a)*(2^5) + 2^a}}}
{{{ 1056 = 32 (2^a) + 2^a }}}
{{{ 1056 = 33 (2^a) }}}
{{{ 32 = 2^a}}}
a = 5