Question 133333
{{{e^x = 2}}} Start with the given equation



{{{ln(e^x) = ln(2)}}} Take the natural log of both sides



{{{x*ln(e) = ln(2)}}} Rewrite the left side using the identity  {{{log(b,(x^y))=y*log(b,(x))}}}



{{{x*(1) = ln(2)}}} Evaluate {{{ln(e)}}} to get 1



{{{x = ln(2)}}} Multiply



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Answer:

So our answer is {{{x = ln(2)}}} which is approximately {{{x=0.6931471806}}}