Question 133306
Given: {{{log4x = 0.5}}}

{{{b^x = y}}} is the same as {{{logb y = x}}}

So {{{log4x = 0.5}}} is the same as {{{4^(0.5) = x}}}
But ^0.5 is the same as sqrt.

So {{{sqrt(4) = x}}}

x = 2