Question 2334
x=# of nickles
y=# of quarters
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We'll have a system of equations...
x + y = 11
.05x + .25y = 1.55
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I'll use substitution.  Solve for "x" in equation #1.
x = 11 - y
Now, plug this in into the second equation...
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.05(11-y)+.25y=1.55
.55-.05y+.25y=1.55
.2y=1.00
y=5
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Now, plug y=5 into either of the orginal equations & solve for "x".  I chosed equation 1 because it looks the easiest.
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x+5=11
x=6
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<b>6 nickels ($0.30)
5 quarters ($1.25)</b>
Thanks
MS