Question 133281
Does your equation look like this: {{{4^x/4 = 1/8}}} ???



{{{4^x/4 = 1/8}}} Start with the given equation



{{{4^x = 4/8}}} Multiply both sides by 4



{{{4^x = 1/2}}} Reduce



{{{(2^2)^x = 2^(-1)}}} Rewrite {{{4}}} as {{{2^2}}}. Rewrite {{{1/2}}} as {{{2^(-1)}}}



{{{2^(2x) = 2^(-1)}}} Simplify




Since the bases are equal, this means that the exponents are equal. So




{{{2x=-1}}}




{{{x=(-1)/(2)}}} Divide both sides by 2 to isolate x




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Answer:


So our answer is {{{x=-1/2}}}  or {{{x=-0.5}}}