Question 133253
Given: Log4(260) = log4(4^x + 3 plus 4^x) 
Thus {{{ 260 = 4^(x + 3) + 4^x }}}
{{{ 260 = 4^(x)*4^3 + 4^x }}}
{{{ 260 = 4^x * (4^3 + 1) }}}
{{{ 260 = 4^x * (64 + 1) }}}
{{{ 260 = 4^x * (65) }}}
{{{ 4 = 4^x }}}
x = 1