Question 133254
Given: {{{log 11 = log(10^(z+4) + 10^(z+3))}}}

Then {{{11 = 10^(z+4) + 10^(z+3) }}}
{{{11 = 10^z * 10^4 + 10^z * 10^3}}}
{{{11 = 10^z * (10000 + 1000)}}}
{{{11 = 10^z * (11000)}}}
{{{0.001 = 10^z }}}
z = -3