Question 133233
During rush hour, Fernando can drive 35 miles using the side roads in the same time that it takes to travel 30 miles on the freeway. If Fernando's rate on the side roads is 9 mi/h faster than his rate on the freeway, find his rate on the side roads. 
I got 63 mi/h 
Is this correct? 
------------------------------------
Side Road DATA;
Distance = 35 miles ; Rate = x+9 mph ; time = 35/(x+9) hrs
--------------------------------------------
Freeway DATA:
Distance = 30 miles ; Rate = x mph ; time = 30/x hrs
--------------------------------------------------
EQUATION:
time = time 
35/(x+9) = 30/x
Cross-multiply to get:
35x = 30x+270
5x = 270
x = 54 mph (freeway driving rate)
x+9 = 63 mph (side road rate)
-------------------------
Looks like you are right. Congratulations.
============================
Cheers,
Stan H.