Question 133153
{{{9^(2x - 1) = 81^(x + 1) * 27^(-x)}}}
{{{(3^2)^(2x - 1) = (3^4)^(x + 1) * (3^3)^(-x)}}}
{{{3^(4x - 2) = 3^(4x + 4) * 3^(-3x)}}}
{{{3^(4x - 2) = 3^(x + 4)}}}
{{{log(3,3^(4x - 2)) = log(3,3^(x + 4))}}}
{{{4x - 2 = x + 4}}}
{{{3x = 6}}}
{{{x = 2}}}