Question 133166
No, sides x,x,p with angles theta, theta, and 180 - 2*theta
x/sin(theta) = p/sin(180 - 2*theta)
p = xcos(theta)
sqrt(x) + sqrt(x) = sqrt(xcos(theta))
(sqrt(x) + sqrt(x))^2 = xcos(theta)
4x = xcos(theta)
0 = xcos(theta) - 4x
0 = x(cos(theta) - 4)
x = 0 which results in no triangle or cos(theta) = 4 which is impossible