Question 133122
6*10=60 SQUARE METERS IS THE AREA OF THE POOL.
THE AREA OF THE WALKWAY PLUS THE WALKWAY IS 2860=120 SQUARE METERS.
(6+2X)(10+2X)=120
60+20X+12X+4X^2=120
4X^2+32X+60-120=0
4X^2+32X-60=0
4(X^2+8X-15)=0
USING THE QUADRATIC EQUATION:{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} WE GET:
X=(-8+-SQRT[8^2-4*1*-15])/281
X=(-8+-SQRT[64+60])/2
X=(-8+-SQRT124)/2
X=(-8+-11.1355)/2
X=(-8+11.1355)/2
X=3.1355/2
X=1.568 METERS IS THE WIDTH OF THE WALKWAY.
1.568(10+2*1.568)*2+2(8+1.568)
1.568(10+3.136)*2+2(9.568)
1.568(13.136)*2+19.14
1.568*26.27+19.14
41.19+19.14
60.32 ANSWER FOR THE AREA OF THE WALKWAY (SHOULD BE 60-EXCESS DUE TO ROUNDING)