Question 133125
A rectangle is 6 cm long and 5 cm wide.  When each dimension is increased by x cm, the total area is tripled.  Find the value of x using algebra.
total area =6*5=30 then
(6+x)(5+x)=3(30)
then x^2+11x+30=90
then x^2+11x+-60=0
then x=(-11+sqrt(361))/2 = 4
or   x=(-11-sqrt(361))/2 =-15
x is >0
then x= 4