Question 133142


Let's denote the first point (2,3) as *[Tex \Large \left(x_{1},y_{1}\right)]. In other words, *[Tex \LARGE x_{1}=2] and *[Tex \LARGE y_{1}=3]


Now let's denote the second point (5,8) as *[Tex \Large \left(x_{2},y_{2}\right)]. In other words, *[Tex \Large x_{2}=5] and *[Tex \Large y_{2}=8]




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{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula


{{{m=(8-3)/(5-2)}}} Plug in {{{y[2]=8}}},{{{y[1]=3}}},{{{x[2]=5}}},{{{x[1]=2}}}



{{{m=5/3}}} Subtract the terms in the numerator {{{8-3}}} to get {{{5}}}.  Subtract the terms in the denominator {{{5-2}}} to get {{{3}}}

  

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Answer:


So the slope of the line through the points (2,3) and (5,8) is {{{m=5/3}}}