Question 133083
{{{25(2x+1)^2/9=0}}} Start with the given equation




{{{cross(9)(25(2x+1)^2/cross(9))=9*0}}} Multiply both sides by 9



{{{25(2x+1)^2=0}}} Multiply





{{{cross(25/25)(2x+1)^2=0/25}}} Divide both sides by 25




{{{(2x+1)^2=0}}} Divide 




{{{2x+1=sqrt(0)}}}  Take the square root of both sides





{{{2x+1=0}}} Take the square root of 0 to get 0



{{{2x=-1}}} Subtract 1 from both sides



{{{x=-1/2}}} Divide both sides by 2 to isolate x.




----------------------------------


Answer: 


So the solution is {{{x=-1/2}}}