Question 20148
Let x be the working rate of first painter and y be the rate of second painter.

Given:
x = (3/2) y

If they together work,they will complete the work in 4 hours.

For one hour first painter works 1/x and second painter 1/y

i.e. 1/x + 1/y = 1/4

     2/3y+1/y=1/4
         
     5/3y = 1/4

    1/y=3/20

For second painter can do the work at the rate 20/3.

For first painter can do the work at the rate (3/2)*(20/3)=10