Question 133005
{{{((49x^2)/(5x^2-20x+20))((5x-10)/(7x))}}} Start with the given expression


{{{(((7*7)(x*x))/(5x^2-20x+20))((5x-10)/(7x))}}}   Factor {{{49x^2}}} to get {{{7*7(x*x)}}} 


{{{(((7*7)(x*x))/(5(x-2)(x-2)))((5x-10)/(7x))}}}   Factor {{{5x^2-20x+20}}} to get {{{5(x-2)(x-2)}}} 


{{{(((7*7)(x*x))/(5(x-2)(x-2)))((5(x-2))/(7x))}}}   Factor {{{5x-10}}} to get {{{5(x-2)}}} 





{{{(7*7)(x*x)5(x-2)/5(x-2)(x-2)7x}}} Combine the fractions



{{{(cross(7)*7)(cross(x)*x)cross(5)cross((x-2))/cross(5)cross((x-2))(x-2)cross(7)cross(x)}}} Combine the fractions



{{{7x/(x-2)}}} Simplify




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Answer:


So {{{((49x^2)/(5x^2-20x+20))((5x-10)/(7x))}}}  simplifies to {{{7x/(x-2)}}}. In other words {{{((49x^2)/(5x^2-20x+20))((5x-10)/(7x))=7x/(x-2)}}}