Question 132965
{{{1-i/1+i*2+i/1+i}}}

i/1 = i
-i/i = -i

Thus we get {{{1 -i +i*2 +i + i}}}

Yielding {{{1 -i +2i + i}}}

Collecting like term yields {{{1 + 2i}}}

If, by chance you meant to write {{{i^2}}} instead of {{{i*2}}} then just do the same steps but substitute -1 for {{{i^2}}}