Question 132912
find the vertex form of {{{ Y= -2x^2-16x-32 }}}.
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2x^2+16x = -(y+32)
2(x^2+8x+16) = -y-32+2*16
2(x+4)^2 = -y
(x+4) = (-1/2)(y-0)
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Vertex: (-4,0)
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{{{graph(400,300,-10,10,-10,10,-2x^2-16x-32)}}}
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Cheers,
Stan H.