Question 20105
{{{x^2-2x=-13}}} take -13 to left changing sign
{{{x^2-2x+13=0}}}a quadratic with no real solutions for x
It does not factor and using formula the discriminant:
{{{sqrt(b^2-4ac)}}}={{{sqrt(4-52)}}}is less than zero.
However if you are the person that sent me{{{x^2-2x=13}}}
by e-mail.This will give solutions.
{{{x^2-2x=13}}} goes to 
{{{x^2-2x-13=0}}}using quadratic formula:
{{{x=(-b+-sqrt(b^2-4*a*c))/(2*a)}}}gives
{{{x=(2+-sqrt(56))/2}}}
{{{x=(1+-sqrt(14))}}}
x=4.7417 and
x=-2.7417
Pete