Question 132828
500/X=500/(X-5)-5
500/X-500/(X-5)=-5
(500(X-5)+X)/X(X-5)=-5
(500X-2500-500X)/(X^2+5X)=-5 CROSS MULTIPLY.
-5(X^2+5X)=-2500
-5X^2+25X+2500=0
-5(X^2-5X-500=0
-5(X-25)(X+20)=0
X-25=0
X=25 NUMBER OF STUDENTS ORIGINALLY PLANNED TO ATTEND.
PROOF:
500/25=500/(25-5)-5
20=(500/20)-5
25=25-5
20=20