Question 132547
you have to cut the corners of the square off


the cut pieces will be 45° isosceles right triangles


the hypotenuse of a cut piece is the length of the side of the octagon


let x="side length of octagon" __ x+2(x/(sqrt(2)))=48 __ x+x(sqrt(2))=48


factoring __ x(1+sqrt(2))=48 __ dividing by (1+sqrt(2)) __ x=48/(1+sqrt(2))


x is approximately 19.88 inches


19.875 is 19 7/8, so the ends of the cuts are 14 1/16 in from the corners of the square