Question 132749
Choice a:  rewrite to {{{y=-4(x+5)^2+2}}}.  This function is defined for all real x, so x < 2 does not make this function undefined.  Incorrect.


Choice b:  x < 2 ensures that the exponent on 4 is positive, but there is nothing wrong with the exponent on 4 being negative or zero, so again, the domain of this function is all reals.  Incorrect.


Choice c: the domain of log(x) is all positive reals.  In order for 4 - 2x to be positive, x must be less than 2.  <b><i>This is the correct function for the given domain.</b></i>


Choice d: again, the domain of log(x) is all positive reals, but in the choice d function, a value for x < 2 would make x - 2 be less than zero.  The domain here is {x|x is Real, x > 2}.  Incorrect.