Question 2304
the term outside the bracket is multiplied by everything inside the bracket, so...

2(n-3) becomes 2n-6
n(2-n) becomes 2n-{{{n^2}}}

so combined we get

2n-6 + 2n-{{{n^2}}} = 2 - {{{n^2}}}

Bring everything onto one side, to give

{{{2n-6 + 2n-n^2 - 2 + n^2 = 0}}}

Now collect like terms...

{{{4n-8 = 0}}}
so, 4n = 8
n=2


jon