Question 132704
2x = 3x^2 + 6
3x^2 - 2x + 6 = 0
x = [2 +- sqrt(4-4*3*6)]/6

x = [2 +- sqrt(-68)]/6

x = [2 +- 2isqrt(17)]/6

x = [1 +- isqrt(17)]/3
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Cheers,
Stan H.