Question 132653
{{{2^(x+1)=1/8}}} Start with the given equation



{{{2^(x+1)=2^(-3)}}} Rewrite 8 as {{{2^(-3)}}}. Notice how the two sides have the same base.



Since the bases are equal, this means that the exponents are equal.




{{{x+1=-3}}} Set the exponents equal to one another




{{{x=-3-1}}} Subtract 1 from both sides



{{{x=-4}}} Combine like terms on the right side


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Answer:

So our answer is {{{x=-4}}}