Question 132556
sqrt ( 9x + 67 ) = x + 5 

{{{sqrt(9x+67)=x+5}}}  square both sides--this will get rid of the radical on the left.

{{{9x+67=(x+5)^2}}}  get rid of parens

{{{9x+67=x^2+10x+25}}}  subtract 9x and also 67 from both sides

{{{9x-9x+67-67=x^2+10x-9x+25-67}}} collect like terms

{{{x^2+x-42=0}}}  quadratic in standard form and it can be factored

{{{(x+7)(x-6)=0}}}
{{{x+7=0}}}
{{{x=-7}}}------------------------one solution
{{{x-6=0}}}
{{{x=6}}}-------------------------the other solution

CK
substituting x=-7
{{{sqrt (4)=-2}}}
+ or - 2=-2---  ok

substituting x=6
{{{sqrt(121)=11}}}
+ or -11=11---ok


Hope this helps---ptaylor