Question 132542
{{{5/x + 4/6 - 3x = 2x/6 - 3x}}}
Right away I see that {{{x}}} can never be {{{0}}} 
because division by {{{0}}} is not allowed
multiply both sides by {{{6x}}}
{{{30 + 4x - 18 = 2x^2 - 18x^2}}}
Combine terms
{{{4x + 12 = - 16x^2}}}
Add {{{16x^2}}} to both sides
{{{16x^2 + 4x + 12 = 0}}}
Divide both sides by {{{4}}}
{{{4x^2 + x + 3 = 0}}}
solve using quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-1 +- sqrt( 1^2-4*4*3 ))/(2*4) }}}
{{{x = (-1 +- sqrt( -47 ))/8 }}}
{{{x = (-1 + sqrt(47)*i)/8 }}} answer
{{{x = (-1 - sqrt(47)*i)/8 }}} answer