Question 132453
{{{y=(-2x^3+6x)/(2x^2-6x))}}}
when x=3 then the denominator=0
So, 3 is the vertical asymptote.
The domain is all real numbers except x=3 and x=0 
Since the numerator is 1 degree larger than the denominator there is no horizontal asymptote but a slant asymptote.
It is -x-3 found by doing long division on the numerator by the denominator.
The almost vertical line is an artifact and not an asymptote.
.
Ed
{{{graph(500,500,-7,13,-30,20,(-2x^3+6x)/(2x^2-6x))}}}