Question 132423
4/3x^2-2x+3/4
Using the quadratic equation:{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} we get:
x=(2+-sqrt[-2*2-4*4/3*3/4])/(2*4/3)
x=(2+-sqrt4-4)/(8/3)
x=(2+-sqrt0)/(8/3)
x=2/(8/3)
x=2*3/8
x=6/8
x=3/4 answer.