Question 132423
(4/3)x^2 - 2x + 3/4 = 0 I assume this is the problem.
a=4/3, b=-2, c=3/4
if the determinant, b^2-4ac is >=0, then it has a real solution.
b^2-4ac=4-4(4/3)(3/4)
=4-4=0
Because the determinant equals zero there is only one answer (0.75).
.
Ed
{{{graph(500,500,-10,10,-10,10,1.33333333x^2-2x+.75)}}}