Question 132426
Which solver did you use? 


{{{6x^4-19x^2+10=0 }}} Start with the given equation



Let {{{u=x^2}}}


{{{6u^2-19u+10=0 }}} Plug in {{{u=x^2}}}



*[invoke quadratic_formula 6, -19, 10, "u"]



Remember, we let {{{u=x^2}}}. So this means that 



{{{x^2=5/2}}} or {{{x^2=2/3}}}



{{{x=0+-sqrt(5/2)}}} or {{{x=0+-sqrt(2/3)}}} Take the square root of both sides for each case



Break up the two expressions


{{{x=sqrt(5/2)}}}, {{{x=-sqrt(5/2)}}}, {{{x=sqrt(2/3)}}}  or {{{x=-sqrt(2/3)}}}  




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Answer:



So our solutions are


{{{x=sqrt(5/2)}}}, {{{x=-sqrt(5/2)}}}, {{{x=sqrt(2/3)}}}  or {{{x=-sqrt(2/3)}}}