Question 132409

{{{x+3/5=6-4(x+2)/10}}} Start with the given equation




{{{(10)(x+3/cross(5))=(10)(6-4(x+2)/cross(10))}}} Multiply both sides by the LCM of 10. This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)




{{{10x+6=60-4(x+2)}}} Distribute and multiply the LCM to each side




{{{10x+6=60-4x-8}}} Distribute



{{{10x+6=-4x+52}}} Combine like terms on the right side



{{{10x=-4x+52-6}}}Subtract 6 from both sides



{{{10x+4x=52-6}}} Add 4x to both sides



{{{14x=52-6}}} Combine like terms on the left side



{{{14x=46}}} Combine like terms on the right side



{{{x=(46)/(14)}}} Divide both sides by 14 to isolate x




{{{x=23/7}}} Reduce


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Answer:

So our answer is {{{x=23/7}}}  (which is approximately {{{x=3.28571}}} in decimal form)