<PRE><B>Question 132356</B>
Let the smallest of the three odd integer be A. The next integer will be (A+2), and the largest of the three is (A+4)

Given:  A + (A+2) + (A+4) = 123

Combine like terms and solve for A as follows
3A + 6 = 123  
Subtract 6 from each side of the equation to yield
3A = 117
Divide both sides by 3. Yields
A = 39

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