Question 132265
B=X SPEED OF THE BUS.
C=2X-30 SPEED OF THE CAR.
DISTANCE=R*T
SEEING AS THE DISTANCES OF THE BUS IS 20 MILES LESS WE HAVE:
2(2X-30)=2X+20 NOTE WE HAVE TO ADD 20 MILES TO THE BUS DISTANCE TO MAKE THEM EQUAL.
4X-60=2X+20
4X-2X=20+60
2X=80
X=80/2
X=40 MPH FOR THE BUS.
C=2*40-30
C=80-30
X=50 PMH FOR THE CAR.
PROOF:
2*50=2*40+20
100=80+20
100=100