Question 20078
let x= first number
so second is x+1
{{{x^2 +(x+1)^2=13}}}multiplying out bracket gives
{{{x^2+x^2+2x+1=13}}}sum and rearrange
{{{2x^2+2x-12=0}}}divide through by 2
{{{x^2+x-6=0}}} a quadratic that factors
(x-2)(x+3)
x=2
x=-3
consecutive numbers are 2 and 3
the minus sign is irrelevant as -3 squared is same as 3 squared
Pete