Question 132282
Maybe you understand it, but you're not giving
exactly the answer requested
You are asked to solve this. That means to find the value
or values of {{{x}}} that make it true
{{{7x + x(x-3) = 0}}}
{{{7x + x^2 - 3x = 0}}}
{{{x^2 + 4x = 0}}}
{{{x*(x + 4) = 0}}}
There are 2 ways this can be true
{{{0*(0 + 4) = 0}}}, making {{{x = 0}}}
and
{{{-4*(-4 + 4)}}}, making {{{x = -4}}}
So the solution(s) are {{{x = 0}}} and {{{x = -4}}}
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Find the x-intercepts of f(x)= 7x + x(x-3)
This is just asking the same question over again
in a different way. It's asking "What values of
{{{x}}} will make {{{f(x) = 0}}}? The answer
is {{{x = 0}}} and {{{x = -4}}}