Question 132225
In the lab there is a vat of a solution of 20% acid and another vat of solution of 50% acid. How much of the 50% acid solution should be mixed with the 20% solution to have 12 gallons of a 30% acid solution?
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50% solution DATA added:
Amount = "x" gallons ; Amt acid is 0.5x gallons 
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20% solution DATA:
Amount = "12-x" gallons; Amt. acid is 0.20(12-x) = 2.4-0.2x gallons
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30% Mixture DATA:
Amount = 12 gallons: Amt acid = 0.30*12 = 3.6 gallons
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EQUATION:
acid + acid = acid
0.5x + 2.4-0.2x = 3.6
0.3x = 1.2
x = 4 gallons ( amount of 50% solution in the mixture)
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Cheers,
Stan H.