Question 132161


Let's denote the first point (-5,0) as *[Tex \Large \left(x_{1},y_{1}\right)]. In other words, *[Tex \LARGE x_{1}=-5] and *[Tex \LARGE y_{1}=0]


Now let's denote the second point (-1,3) as *[Tex \Large \left(x_{2},y_{2}\right)]. In other words, *[Tex \Large x_{2}=-1] and *[Tex \Large y_{2}=3]




-------------------------




{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula


{{{m=(3-0)/(-1--5)}}} Plug in {{{y[2]=3}}},{{{y[1]=0}}},{{{x[2]=-1}}},{{{x[1]=-5}}}



{{{m=3/4}}} Subtract the terms in the numerator {{{3-0}}} to get {{{3}}}.  Subtract the terms in the denominator {{{-1--5}}} to get {{{4}}}

  

---------------------

Answer:


So the slope of the line through the points (-5,0) and (-1,3) is {{{m=3/4}}}



So you are correct