Question 132134
{{{2x^2-12x+18=0}}}
   {{{2x^2-6x-6x+18=0}}}    
   {{{2x(x-3)-6(x-3)}}}=0
   (x-3)(2x-6)=0
    x-3=0
    x=3
    2x-6=0
    2x=6
     {{{2x/2}}}={{{6/2}}}
      x=3

{{{2x^2-18}}}
{{{2(x^2-9)}}}
{{{2(x^2-3^2)}}}
2(x-3}(x+3)       since  {{{a^2-b^2}}}=(a-b)(a+b)            

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