Question 132130
1) (6-i)(3+2i)

TO solve, keep in mind that i^2 = -1.  We are dealing with complex numbers.

For question 1, use the FOIL METHOD.

6 times 3 = 18

6 times 2i = 12i

-i times 3 = -3i

-i times 2i = -2(i)^2

Like I said above, i^2 = -1

Then, -2(-1) = 2

We now have this:

18 + 12i - 3i + 2

Combine like terms.

9i + 20

Rearrange the terms to get 20 + 9i.

==================================

(2) 3i(6+4i)

For this question, use the distributive rule to remove the parentheses.

3i times 6 = 18i

3i times 4i = 12(i)^2

Of course, i^2 = -1 and so, 12(i)^2 = -12

We now have this:

18i - 12

Rearrange the terms and we get:

-12 + 18i

That's it!