Question 132129
negative a to the negative n, times a to the n minus 1, times a to the 1, times negative a to the negative n, over a to the negative n.
Does it look like this: {{{(-a^(-n)*a^(n-1)*a^1*(-a^(-n)))/(a^(-n)) }}}???


If so, then notice that the factors of {{{a^(-n)}}} on the right side of the numerator and the denominator divide out, leaving a factor of -1.


{{{-a^(-n)*a^(n-1)*a^1*(-1) }}}



Next, the negative of a negative is a positive:
{{{a^(-n)*a^(n-1)*a^1 }}}


What is left is all with base number a, so write down the base number and add exponents:
{{{a^(-n+n-1+1)}}}
{{{a^0}}}
{{{1}}}


R^2