<PRE><B>Question 132116</B>
three times the largest of three consecutive odd integers is three less than twice the sum of the other two integers. find the integers.
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1st: 2x+1
2nd: 2x+3
3rd: 2x+5
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EQUATION:
3(2x+5)= 2(2x+1+2x+3)-3
6x+15 = 2(4x+4)+3
6x+15 = 8x+11
2x= 4
x = 2
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1st: 5
2nd: 7
3rd: 9
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Cheers,
Stan H.</PRE>