Question 132107
Mark is 10 years younger then Larry.
Larry's age in 8 years will exceed 
twice Mark's age 3 years ago by 4 years.
How old is each now?
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NOW DATA:
Let Larry's age be "x": Mark's age is "x-10"
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In 8 years years Larry will be x+8
x-13 (Mark;s age three years ago)
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EQUATION:
x+8 = 2(x-13)+4
x+8 = 2x-22
x = 30 (Larry's age now)
x-10 = 20 (Mark's age now)
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Cheers,
Stan H.