Question 132045
I think you are trying to represent {{{x^2(2x+10)(x-5)=0}}}.


Use the idea that {{{a*b*c=0}}} if and only if a = 0 or b = 0 or c = 0.


In your problem, {{{x^2(2x+10)(x-5)=0}}} if and only if {{{x^2=0}}} or {{{2x+10=0}}} or {{{x-5=0}}}


If {{{x^2=0}}}, then {{{x=0}}}


If {{{2x+10=0}}}, then {{{2x=-10}}}, {{{x=-5}}}


If {{{x-5=0}}}, then {{{x=5}}}


So the solution set is {-5,0,5}, because any of these values when substituted for x will make the original equation a true statement.


By the way, please avoid using ALL CAPS.  It is annoying, rude, and the electronic communication equivalent of shouting.